C/C++仿華容道小游戲
本文實(shí)例介紹了C++模仿華容道小游戲?qū)崿F(xiàn)代碼,分享給大家供大家參考,具體內(nèi)容如下
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <stdbool.h>
#define maxnum 16
#define colnum 4
bool numexists(int *numbers, int length, int num);
int getnumber(int **numbers, int randIndex, int *length);
int* initnumbers(void);
void swap(int **a, int **b);
int main(int argc, char *argv[])
{
int *tempnumbers = initnumbers();
int *randnumbers = initnumbers();
int **numbers;
numbers = malloc(maxnum * sizeof(int*));
//bool a = numexists(numbers, 16, 3);
//printf("a=%d\n", a);
int length = maxnum;
srand((unsigned)time(NULL));
for (int i = 0; i < maxnum; i++)
{
int temp = getnumber(&tempnumbers, rand() % length, &length);
randnumbers[i] = temp;
numbers[temp] = &randnumbers[i];
//printf("%d%c", temp, (i + 1) % colnum == 0?'\n':'\t');
}
if (tempnumbers != NULL)
free(tempnumbers);
while (true)
{
system("clear");
for (int i = 0; i < maxnum; i++)
printf("%d%c", randnumbers[i], (i + 1) % colnum == 0?'\n':'\t');
printf("move number/ invalid num==exit: ");
int i;
if (!scanf("%d", &i))
{
printf("game over\n");
break;
}
if (i >= maxnum || i <0)
{
printf("sorry, i can't find %d\n", i);
break;
}
unsigned char sign = abs(numbers[i] - numbers[0]);
switch (sign)
{
case 1:
case 4: swap(&numbers[0], &numbers[i]); break;
}
}
if (numbers != NULL)
free(numbers);
if (randnumbers != NULL)
free(randnumbers);
}
void swap(int **a, int **b)
{
int *templocation = *a;
int tempvalue = **a;
**a = **b;
**b = tempvalue;
*a = *b;
*b = templocation;
}
int* initnumbers(void)
{
int *numbers = malloc(maxnum * sizeof(int));
for (int i = 0; i < maxnum; i++)
numbers[i] = i;
return numbers;
}
int getnumber(int **numbers, int randIndex, int *length)
{
int result = (*numbers)[randIndex];
(*numbers)[randIndex] = (*numbers)[--(*length)];
int *temp = realloc(*numbers, (*length) * sizeof(int));
*numbers = temp;
return result;
}
bool _numexists(int *numbers, int start, int end, int num)
{
printf("start: %d, end: %d, num: %d\n", start, end, num);
if (start == end)
return numbers[start] == num;
else
{
int middle = (start+end) / 2;
if (numbers[middle] == num)
return true;
else if (numbers[middle] > num)
return _numexists(numbers, start, middle-1, num);
else
return _numexists(numbers, middle+1, end, num);
}
}
bool numexists(int *numbers, int length, int num)
{
return _numexists(numbers, 0, length-1, num);
}
希望本文對(duì)大家學(xué)習(xí)C++程序設(shè)計(jì)有所幫助。
上一篇:C++求Fib數(shù)列
欄 目:C語(yǔ)言
本文標(biāo)題:C/C++仿華容道小游戲
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